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286 char* and char[] are different types, but it's not immediately apparent in all cases The trick is that arrays are laid out contiguously in memory, so given a pointer to the first element of an array, you can access the other elements by simply adding an offset to the pointer. This is because arrays decay into pointers, meaning that if an expression of type char[] is provided where one of type char* is expected, the compiler automatically converts the array into a pointer to its first element.
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The char type can only represent a single character A char* does point to a single char When you have a sequence of characters, they are piled next to each other in memory, and the location of the first character in that sequence is returned (assigned to test)
Test is nothing more than a pointer to the memory location of the first character in testing, saying that the type it points to is a char.
15 char **x is a pointer to a pointer, which is useful when you want to modify an existing pointer outside of its scope (say, within a function call) This is important because c is pass by copy, so to modify a pointer within another function, you have to pass the address of the pointer and use a pointer to the pointer like so: Is a pointer to the literal (const) string test The main difference between them is that the first is an array and the other one is a pointer
The array owns its contents, which happen to be a copy of test, while the pointer simply refers to the contents of the string (which in this case is immutable). Technically, the char* is not an array, but a pointer to a char Similarly, char** is a pointer to a char* Making it a pointer to a pointer to a char
50 the difference between char* the pointer and char[] the array is how you interact with them after you create them
If you are just printing the two examples, it will perform exactly the same They both generate data in memory, {h, e, l, l, o, /0} The fundamental difference is that in one char* you are assigning it to a pointer, which is a. Use cout << q to print single character.
You are using the string %s specifier with a char data type (ie If you are printing a single character, you use the %c format specifier, and the matching argument should be a character (ie // foo is a pointer to a char, but bar is just a char it is primarily for this reason that the asterisk is conventionally placed immediately adjacent to the identifier and not the type, as it avoids this confusing declaration.
